How many of them are apples?

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In a huge pile of apples & oranges, both ripe & unripe mixed together, $15 \text{%}$ are unripe fruits. Of the unripe fruits, $45 \text{%}$ are apples. Of the ripe ones, $66 \text{%}$ are oranges. If the pile contains a total of 5692000 fruits, how many of them are apples?

$a) \ 2029198 \ \ \ \ \ \ \ \ \ \ \ b) \ 2467482 \ \ \ \ \ \ \ \ \ \ \ c) \ 2789080 \ \ \ \ \ \ \ \ d) \ 3577422 $

my try:

number of unripe fruits $=\frac{15}{100}\cdot 5692000=853800$

number of apples $=\frac{45}{100}\cdot 853800=384210$

but the correct answer is a) $2029198$ but i don't know how to reach this answer. some please help me or give me some hint to solve it.

thanks

2

There are 2 best solutions below

0
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Hint: There are also ripe apples. Any ripe fruit that is not an orange is a ripe apple.

2
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You have only given the number of unripe apples. Out of the remaining ripe fruit, which total $85$ percent of $5692000$, $100-66 = 34$ percent of those are apples. You must add those into your total, and you will obtain $2029198$.