In a huge pile of apples & oranges, both ripe & unripe mixed together, $15 \text{%}$ are unripe fruits. Of the unripe fruits, $45 \text{%}$ are apples. Of the ripe ones, $66 \text{%}$ are oranges. If the pile contains a total of 5692000 fruits, how many of them are apples?
$a) \ 2029198 \ \ \ \ \ \ \ \ \ \ \ b) \ 2467482 \ \ \ \ \ \ \ \ \ \ \ c) \ 2789080 \ \ \ \ \ \ \ \ d) \ 3577422 $
my try:
number of unripe fruits $=\frac{15}{100}\cdot 5692000=853800$
number of apples $=\frac{45}{100}\cdot 853800=384210$
but the correct answer is a) $2029198$ but i don't know how to reach this answer. some please help me or give me some hint to solve it.
thanks
Hint: There are also ripe apples. Any ripe fruit that is not an orange is a ripe apple.