Trying to work out this problem:
The answer is the summation from $k = 0$ to $n$ for $(-1)^k \binom {n} {k} (2n - k)! \ 2^k $
Trying to work out this problem:
The answer is the summation from $k = 0$ to $n$ for $(-1)^k \binom {n} {k} (2n - k)! \ 2^k $
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