In a factory, $1$ liter of fruit juice contains water cost, fruit concentrate cost and packing cost.
There's fruit concentrate $\%25$ of water in the fruit concentrate and water mixture.
Water cost equals $\%30$ of fruit concentrate cost.
Packing cost is $0.32\$$
If you sell $1$ liter of fruit juice with the price of $2.4\$$ which gives $\%100$ of profit, How much does the fruit concentrate cost in $1$ liter of fruit juice?
Let's recall $F =$ fruit concentrate cost, $W = $ Water cost and $P= $ packing cost,
$$W + F + \underbrace{P}_{0.32} = 1.2$$
Which yields
$$W + F = 0.88$$
Water cost equals $\%30$ of fruit concentrate cost.
$$W = \dfrac{30}{100}F$$
Then we have that
$$F + \dfrac{30}{100}F = 0.88 \implies F = 0.67692$$
I can't think of any way to proceed right now.
Regards!
You are correct up to the point where you compute that the cost of the water plus the cost of the fruit concentrate is $88$ cents in a liter of the product.
The sentence "There's fruit concentrate %25 of water in the fruit concentrate and water mixture," is rather awkward. I guess it means that the amount of fruit concentrate in the mixture is $25\%$ of the amount of fruit concentrate, or that a liter of the product contains $200$ ml of fruit concentrate and $800$ ml of water.
Let $x$ be the cost of a liter of fruit concentrate. A liter of water costs $30\%$ of this or $.3x.$ Since we only have $20\%$ of a liter of fruit concentrate in a liter of mixture, the cost of the concentrate is $.2x.$ Also, we have $80\%$ of a liter of water, so the cost of the water is $.8(.3x)=.24x$ Then the cost of the concentrate and water in a liter of product is$$ .2x +.24x=.44x$$ Since we've already determined that the cost of the of the water and concentrate is $88$ cents we have $$ .44x=88\implies x=200\text{ cents}$$
EDIT
I misread the question. I thought we were looking for the cost of a liter of fruit concentrate, but it's actually the cost of the amount of fruit concentrate in a liter of the mixture. That's $20\%$ of $200$ cents or $40$ cents.