How much is 4.181,203,352,191,774,5e+33?

Question

I am trying to figure out how many possible combinations a 17 character password has. Using elPassword, I got an answer of 4.181,203,352,191,774,5e+33, but I have no idea what that means. How much is that?

(Also, I have no idea what tags this fits under, but saw that the exponential-function tag was also known as e, so if you have any suggestions, please let me know)

Answer 1

Apparently you allow $95$ characters, for $$ 95^{17}=4\,181\,203\,352\,191\,774\,128\,676\,605\,224\,609\,375$$

Answer 2

The e+33 means $\times 10^{33}$, so this number has a 4 at the front and is followed by 33 more digits, 16 of which you know. The fancy name for $10^{33}$ is a 'decillion', so your number is approximately four decillion.