How is calculated the memory that is needed for matrix of $2^{14}$ by $2^{24}$ double precision real numbers ?
Matlab stops responding with 32Gb ram.
2026-03-30 15:34:51.1774884891
How much RAM is needed for $2^{14}$ square grid of double numbers?
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A double precision number requires $8$ bytes of storage. The total number of bytes needed is then the number of double precision numbers multiplied by the number of bytes needed to store each. We have \begin{equation} \text{# bytes } = 8\cdot2^{14}\cdot2^{24} = 2^3\cdot2^{14}\cdot2^{24} = 2^{41}, \end{equation} which is approximately $2.2$ Terabytes.