$$(2x + 1)(3x - 5) - 4x(x-3) + 7 \leq 0$$ (is less or equal than "0", someone help me to edit that part).
Step 1:
$$6x^2 - 10x + 3x - 5 - 4x^2 + 12x + 7 \leq 0$$
Step 2:
$$2x^2 - 19x + 7 \leq 0$$
Step 3:
$$ x = \frac{19 + \sqrt{-(19)^2 - 4(2)(7)}}{2(2)}$$
Step 4:
$$ x_1 = 9.125$$ $$ x_2 = 0.375$$
But, how to give a SC answer? There is no intersection for the X1 and X2. So the solution in null?
HINT: after expanding we obtain $$2x^2+5x+2<0$$ this can be factorized into $$(x+2)(2x+1)<0$$