How to begin solving this cyrptarithm?

Question

Anybody please help me in how to begin with this cryptarithm. I tried to find for 0,1,5,6,9 but none of them are clearly recognizable..

o u i * o u i

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   l i a r
 m l m a 

t h u s

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m s i e u r

Answer 1

Starting hint:

First note that there are 11 symbols in cryptarithm: o,u,i,l,a,r,m,t,h,s,e.
So, in decimal system, at least two of symbols are equal.

A). t +1 = m. $\ \ \implies \ $ thus < mlma $\ \ \implies \ $ oui*o < oui*u $\ \ \implies \ $ o < u.

B). oui*oui = msieur $\ \ \implies \ $ m $\le$ o, $\ \ $ o $\ge$ $3$.

C). So we get: $\ \ 0$ < t < m $\le$ o < u $\ \ \ \ $ ( t + 1 = m ).

D). Applying comment of Gerry Myerson, we search "ui", such that u $\ge$ 4,

_ui * _ui = ____ur,

and get 6 possible cases:

_43 * _43 = ____49,
_63 * _63 = ____69,
_69 * _69 = ____61,
_74 * _74 = ____76,
_76 * _76 = ____76,  (here i=r=6),
_83 * _83 = ____89.

E). Now we search "oui", where o $\ge$ $3$, and

oui * u = mlma.

_43: no results;
_63: no results;
_69: no results;
_74: no results;
_76: 476 * 7 = 3332;
_83: 783 * 8 = 6264.

F). There are 2 possible numbers for "oui": $476$ and $783$.

$783$ * $783$ works, but a=h=4 (because there are 11 symbols in cryptarithm: o,u,i,l,a,r,m,t,h,s,e).