How to calculate inverse Laplace transform of $F(S)=\frac{se^{-3s}}{s^2+22s+125}$

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$$F(S)=\frac{se^{-3s}}{s^2+22s+125}$$

My first reflex was to attempt a decomposition into partial fractions, but I am simply left with a fraction that is just as "complicated", instead of the usual decomposition into multiple simpler fractions separated by addition/subtraction/etc.

P.S. To save you some time, it is sufficient to show me how to get a decomposed fraction from this fraction, I can do the actual inverse laplace transforms from there.

Thank you!

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Hint:

Solve $s^2+22s+125=0$. This yields $$s_1= -11 - 2i,\quad s_2=-11+2i$$

Now $$f(t)= \operatorname{Res}_{s=s_1}(F(s)\cdot e^{st})+\operatorname{Res}_{s=s_2}(F(s)\cdot e^{st}).$$

Calculate the residues by factoring the denominator with $s_1$ and $s_2$ and then calculate the limit, without any indeterminate form.