I do not need a specific answer, but a global formula that solves this equation.
There is a coin that costs 100\$ (or 5\$ or \$25 etc.) Each year, it steadily increases by 10% (or 1% or 4% etc.) How much did the coin cost 3 years ago?
X = price
Y = percent of increases
t = time
Thank you for help.
Let's say the coin costs $x_0\$$ at present. And its value increases monotonically by y% every year. Let the cost of the coin t years before was $x_{-t}\$$. Therefore,
\begin{align} &\implies x_{-t} \left(\frac{y}{100}+1\right)^t=x_0\\ &\implies x_{-t}= x_0\left(\frac{y}{100}+1\right)^{-t} \end{align}
Here, $x_{-t}\frac{y}{100}+x_{-t}$ is the increase in value $'t'$ years before.