How to calculate this $\sum\limits_{n=0}^{\infty}\frac{n}{2^n}e^{-jwn}$,because it is not geometric progression,so i can't know how to solve it,can anyone help me?
2026-03-28 01:48:21.1774662501
How to calculate this $\sum\limits_{n=0}^{\infty}\frac{n}{2^n}e^{jwn}$
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For $|z|<1$ we have $\sum_{n=0}^{\infty}n z^n= \frac{z}{(1-z)^2}$.
Now let $z= \frac{e^{-jw}}{2}$. Can you proceed ?