I want to calculate
$$\sum_{n=0}^{\infty}\frac{(2n)!}{n!(n+1)!}k^{n+1}C$$
where $0<k<1$ and $C$ and $k$ are some constants, and $0<C$. Is there any possible range of $0<C$ that allows easy calculation of this?
In general, how do I solve this sum?
I want to calculate
$$\sum_{n=0}^{\infty}\frac{(2n)!}{n!(n+1)!}k^{n+1}C$$
where $0<k<1$ and $C$ and $k$ are some constants, and $0<C$. Is there any possible range of $0<C$ that allows easy calculation of this?
In general, how do I solve this sum?
Hint: Differentiate with regard to the parameter k, and identify the binomial series behind the new expression.