How to compute $\sum_{n=1}^{\infty}\frac{1}{n2^n}$

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How to compute $\sum_{n=1}^{\infty}\frac{1}{n2^n}$?

I think it convergences but do not know how to compute it.

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HINT

Let $f(x) = \sum_{n=1}^\infty x^{n-1}$ for $0<x<1$ and compute $F(x) = \int f(x) dx$. The consider $F(1/2)$.