How to define the induced map of shifted complexes?

23 Views Asked by At

First question here. Apologies for any rookie mistakes, gladly take comments on how to improve phrasing etc.

Conventions: I define $[k]$ to be the one-dimensional vector space concentrated in degree $-k$. Define $A[k]:= [k]\otimes A$. I also work with the Koszul sign convention.

Let $f: A\to B$ be a map of cochain complexes of degree $n$. Let's say I want to define a map $f': A[k]\to B[l]$ using $f$. There is at least two ways of doing so.

  1. $f'= ([l]\otimes -)\circ f \circ ([-k]\otimes- )$,
  2. $f'= ([l-k]\otimes -)\circ 1(\otimes f)$,

where $([x]\otimes -)$ means "tensoring from the left". Option 2 will then come with an extra sign $(-1)^{nk}$.

My question is: What are the pros/cons of choosing one over the other?

Naively I would like to use 1. since it produces less signs. But in the literature, especially when defining shifted cochain complexes I have seen option 2 more frequently used (e.g. let $(A,d)$ be a cochain complex, then $(A[k],d_{[k]})$, where $d_{[k]}(a[k])=(-)^k(da)[k]$ is the shifted cochain complex).