How to derive curl in spherical coordinates

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This is one of those questions where I know I am making a dumb mistake someplace and I am trying to check where it is.

$$ \begin{vmatrix} \frac{\bf\hat r}{r^2\sin\theta} & \frac{\bf\hat \theta}{r\sin\theta} & \frac{\bf \hat\phi}{r} \\ \frac{\partial}{\partial r} & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial \phi} \\ u_r & ru_{\theta} & r\sin\theta u_{\phi} \\ \end{vmatrix}=\nabla \times \bf u $$

So far so good, but for some reason when I take the determinant I am not gettinghte usual formula for $\nabla \times \bf u$. So let's break it down:

Term 1: $\frac{\bf\hat r}{r^2\sin\theta} \left[\frac{\partial}{\partial \theta}(r\sin\theta u_{\phi})-\frac{\partial}{\partial \phi}( ru_{\theta} )\right]=\frac{\bf\hat r}{r\sin\theta} \left[\frac{\partial}{\partial \theta}(\sin\theta u_{\phi})-\frac{\partial u_{\theta}}{\partial \phi}\right]$

so far so good.

But then I get to term 2. it should be: $\hat\theta\frac{1}{r}\left[\frac{1}{\sin \theta}\frac{\partial u_r}{\partial \phi}- \frac{\partial}{\partial r}(ru_{\phi})\right]$

but I get: $\hat\theta\frac{-1}{r\sin\theta}\left[\frac{\partial}{\partial r}(r\sin\theta u_{\phi})- \frac{\partial}{\partial \phi} (u_r)\right]=\hat\theta\frac{1}{r}\left[-\frac{\sin\theta u_{\phi}}{\sin \theta}+\frac{\partial u_r}{\partial \phi}\frac{1}{\sin \theta} \right]=\hat\theta\frac{1}{r}\left[-{u_{\phi}}+\frac{\partial u_r}{\partial \phi}\frac{1}{\sin \theta} \right]$

(The -1 in the second term is b/c when taking a determinant you subtract the second term)

anyhow i get the sense i did something silly. But am having trouble figuring out what.

thanks folks.

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If

$\frac{\partial}{\partial r}(ru_{\phi}) = u_{\phi}$

then you're all right. Everything else looks the same in that component of the curl.

As long as $u_\phi$ doesn't depend on $r$, it should, right?