How to determine the eigenvector in the case of $\lambda=\infty$?

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Let $A=\begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix}$, $B=\begin{pmatrix} 0 & 0 \\ 0 & 1 \end{pmatrix}$ we want to determine the eigenpairs of the general eigenvalue problem.

From the following properties we have:

$(\lambda,x) $ eigenpair of $(A,B) \iff (A-\lambda B)x=0$ , $x\ne 0$.

Then we have $P(\lambda)=-\lambda \Rightarrow \sigma(A,B)=\{ 0,\infty\}$

My question is how to determine the eigenvector in the case of $\lambda=\infty$ ?