Can someone give me the process to differentiate this (with respect to $x$)?
$$ \ln(a^x) $$
Since $$\ln(a^x) = x\ln a,$$ you can see that this function is in fact linear in $x$. (Note that $\ln a$ is just some constant.) The derivative is therefore $1 \cdot \ln a= \ln a.$
Hint:
Use the fact that $$a^x = e^{x\ln a}.$$
Copyright © 2021 JogjaFile Inc.
Since $$\ln(a^x) = x\ln a,$$ you can see that this function is in fact linear in $x$. (Note that $\ln a$ is just some constant.) The derivative is therefore $1 \cdot \ln a= \ln a.$