How to divide $6^{4/6}$ by $6^{6/8}$?

Question

How do you resolve this: base 6 and exponent 4/6 divided by base 6 and exponent 6/8?

Answer 1

Use the exponent rule $\dfrac{x^a}{x^b}=x^{a-b}$.

$$\dfrac{6^{4/6}}{6^{6/8}}=6^{4/6-6/8}=6^{-1/12}=\dfrac{1}{\sqrt[12]{6}}$$