I was wondering how does one estimate $$ \sum_{2 \leq n \leq X} \frac{1}{(\log n)^A}? $$ where $A>0$. I feel like it should be $\ll \frac{X}{(\log X)^A}$... Any comments would be appreciated. Thank you.
2026-04-09 05:34:35.1775712875
How to estimate $\sum_{2 \leq n \leq X} \frac{1}{(\log n)^A} $?
30 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in REAL-ANALYSIS
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