How to expand $2^6 \cos^7(x)$
The answer is $\cos(7x) +7\cos(5x) +21\cos(3x) +35\cos(x)$.
$$2\cos{(nx)}=e^{inx}+e^{-inx}$$ $$(2\cos{(x)})^7=(e^{ix}+e^{-ix})^7$$ $$=(e^{i7x}+e^{-i7x})+7(e^{i5x}+e^{-i5x})+21(e^{i3x}+e^{-i3x})+35(e^{ix}+e^{-ix})$$ $$=2\cos{(7x)}+14\cos{(5x)}+42\cos{(3x)}+70\cos{(x)}$$
Copyright © 2021 JogjaFile Inc.
$$2\cos{(nx)}=e^{inx}+e^{-inx}$$ $$(2\cos{(x)})^7=(e^{ix}+e^{-ix})^7$$ $$=(e^{i7x}+e^{-i7x})+7(e^{i5x}+e^{-i5x})+21(e^{i3x}+e^{-i3x})+35(e^{ix}+e^{-ix})$$ $$=2\cos{(7x)}+14\cos{(5x)}+42\cos{(3x)}+70\cos{(x)}$$