Express $$\cos \Bigg(\frac{3\pi}{2} + x\Bigg)$$ in terms of $\sin x$ and $\cos x$
My try:
$$\cos \Big(\frac{3\pi}{2} + x\Big)=\cos \frac{3\pi}{2} \cos x-\sin \frac{3\pi}{2} \sin x=0-(-1)\sin x=\sin x$$
Is this the correct way to do it?
Express $$\cos \Bigg(\frac{3\pi}{2} + x\Bigg)$$ in terms of $\sin x$ and $\cos x$
My try:
$$\cos \Big(\frac{3\pi}{2} + x\Big)=\cos \frac{3\pi}{2} \cos x-\sin \frac{3\pi}{2} \sin x=0-(-1)\sin x=\sin x$$
Is this the correct way to do it?
Recall the identities for sine and cosine in the four quadrants. One of the QIV identities is the following. $$\cos\big(\frac{3\pi}{2}+x\big) = \sin x$$