How to extract factor when expression is with a power

Question

$$f(x) = x^2(2x-3)^3$$

I tried to extract the 2 from the parenthesis.

$$f(x) = 2x^2(x-\frac{3}{2})^3$$

But the graphic from this function is different.

What should I consider when doing this kind of factoring?

Answer 1

$f(x)=8x^{2}(x-3/2)^{3}$ and not $2x^{2}(x-3/2)^{3}$. This is because since $2(x-3/2)=2x-3$, when taking the third power the $2$ becomes an $8$.

Answer 2

$f(x) = x^2 * ((2)(x-3/2))^3$

 = x^2 * (2)^3 (x-3/2)^3