or $$ s^2+s\frac{R}{L}+\frac{2}{LC}=0 $$
Is there any way? I can't find out. Thanks in advance.
$$s^2+s\frac{R}{L}+\frac{2}{LC}=\left(s-\frac{-\frac RL+\sqrt{\frac{R^2}{L^2}-\frac{8}{LC}}}{2}\right)\left(s-\frac{-\frac RL-\sqrt{\frac{R^2}{L^2}-\frac{8}{LC}}}{2}\right)$$
HINT:
We can complete the square by writing
$$s^2+\frac RL s+\frac2{LC}=\left(s+\frac{R}{2L}\right)^2-\left(\frac{R^2}{4L^2}-\frac{2}{LC}\right)$$
Can you factor this?
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$$s^2+s\frac{R}{L}+\frac{2}{LC}=\left(s-\frac{-\frac RL+\sqrt{\frac{R^2}{L^2}-\frac{8}{LC}}}{2}\right)\left(s-\frac{-\frac RL-\sqrt{\frac{R^2}{L^2}-\frac{8}{LC}}}{2}\right)$$