How to find $10^{-1}$ in $\{0, 2, 4, 6, 8, 10, 12\} \subseteq \mathbb Z_{14}$?

110 Views Asked by At

Here is my question:

  1. Consider the subset $S = \{0, 2, 4, 6, 8, 10, 12\}$ in $\mathbb Z_{14}$, with the operations of addition and multiplication in $\mathbb Z_{14}$.

    (a) Show that $S$ has a multiplicative identity: that is, find a specific element $x$ of $S$ for which $x\cdot a = a$ for each element $a \in S$.

    • Make a multiplication table for $S$. Remember that the multiplication is in $\mathbb Z_{14}$. Your table should contain only the elements ${0, 2, 4, 6, 8, 10, 12}$. Look at the table to find the identity.

    (b) Using the multiplicative identity you found in part (a), what is $10^{−1}$? That is, what element multiplied by $10$ gives your multiplicative identity?

For part (a), I found the answer, $x=8$. For part (b), I am stuck, even though it's probably simple.

So, I need to find where $10X = 1$ in $\mathbb Z_{14}$, correct? But anything in $\mathbb Z_{14}$ multiplies by 10 will be even, and therefore will not be $1$. Or am I missing something? Thanks!

1

There are 1 best solutions below

2
On

You want $10 x = e$ where $e$ is the answer to $(a)$