I have got a set of problems
√2-√3
√8/√2
And i have to find if the result of the problem is going to be a rational or irrational number.How can i do that considering that we know which part of problem is a rational and which part is irrational number?
Assume that $\sqrt2-\sqrt3$ is rational.
Then, $\sqrt2+\sqrt3 = \dfrac1{\sqrt3-\sqrt2}$ is also rational.
Therefore, $(\sqrt2+\sqrt3)+(\sqrt2-\sqrt3)=2\sqrt2$ is also rational.
Therefore, $\sqrt2$ is rational.
This is a contradiction, so $\sqrt2-\sqrt3$ is irrational.
$\dfrac{\sqrt8}{\sqrt2}=2$ is rational.