How to find out the laplace transform of $$f(t) \cdot \sum_{i=1}^\infty a_i g_i(t),$$ w.r.t the variable $t$ on the domain $[0,\infty)$, where $a_i$'s are constants with value $0\le a_i\le1$.
How to find out the laplace transform of the product of two functions?
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In general, if $F(s) = \mathcal{L} \left\{ f(t) \right\}$ and $G(s) = \mathcal{L} \left\{ g(t) \right\}$, the Laplace transform of the product can be found in that way:
$$\mathcal{L} \left\{ f(t)g(t) \right\} = \frac{1}{2\pi i}\lim_{T \to \infty} \int_{c -iT}^{c+iT} F(\sigma)G(s-\sigma)d\sigma = \frac{1}{2\pi i} \lim_{T \to \infty} \int_{c -iT}^{c+iT} F(s - \sigma)G(\sigma)d\sigma ,$$
where $c$ is any constant such that $ c + ia $ is in the region of convergence of F for every $a \in \mathbb{R}$.
But I think I'm not trully understanding your question. Have you said that $f,g_i$ are constant functions on their domain? Then you can express them as linear combinations of heavyside step functions and their Laplace transform will be easier to find.
Then, if they are just continuous functions, I only see 2 ways to get the Laplace transform of $h(t) = f(t) \sum_{i=1}^{\infty} a_i g_i(t) $:
Considering $F(s) = \mathcal{L}\left\{ f(t) \right\}$, $G_i(s) =\mathcal{L}\left\{ g_i(t) \right\}$ for each $i \in \mathbb{N}$. Since the Laplace transform is a lineal operator, for every $n \in \mathbb{N}$ we have that $\mathcal{L}\left\{ \sum_{i=1}^n a_i g_i(t)\right\} = \sum_{i=1}^n a_i G_i(t)$. I'm not sure if there is any problem with linear combinations of infinitely many functions, so you may prove that $\mathcal{L}\left\{ \sum_{i=1}^{\infty} a_i g_i(t)\right\} = \sum_{i=1}^{\infty} a_i G_i(t)$ (as a limit, at least). And then, use the rule I gave you in the other answer.
If you don't need the Laplace transform of $h(t)$ to depend on the Laplace transforms of $f$ and $g_i$ and you have more information about them, try to do it as a unique function. But for this you need to know explicitely (or at least, "better"), $f(t)$ and the $g_i(t)$ (or directly $h(t)$).
I'm working in a similar problem and I used the power series developement of one of the functions. Since $\mathcal{L}\left\{ t^n f(t) \right\} = (-1)^n \frac{d^n}{ds^n}\mathcal{L}\left\{ f(t) \right\}$, I obtained the Laplace transform of the product as a series on the derivatives of the Laplace transform of one of the functions in the product. But I don't think this is a good way.
I hope it has been helpfull!