Square with 2 quarter circles. Square has sides 4 and the circles go from 1 top corner to the opposite bottom corner. The two quarter circles intersect in the middle, and a shape is left at the top. I need the perimeter of that shape. Thanks.
2026-04-30 08:01:11.1777536071
How to find remaining perimeter of shape in a 4cm square with 2 quarter circle centers on bottom corners?
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1
Well, though it is not very clear from the question but making few assumptions, I think you are looking for this.
The triangle formed by the point of intersection of the quadrants and the bottom corners is an equilateral triangle. Now, for the first quadrant angle opp to $l_1$ is $\frac{\pi}{6}$ and thus $l_1=\frac{R\pi}{6}$.