How do I get the values of $x$ and $y$, without using the quartic formula?
\begin{align*} \begin{cases} x+y^2-4=0 \\ y+x^2-4=0 \end{cases} \end{align*}
2026-03-27 02:37:39.1774579059
How to find result of system $x+y^2-4=0$ and $y+x^2-4=0$ without using the quartic formula
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Subtract the first equation from the second to obtain: $$x^2-y^2+y-x=0\Leftrightarrow \\ (x-y)(x+y-1)=0 $$