Recently I thought, could you calculate the area of a triangle (scalene) when you have:
- 2 sides of a triangle with the angle between them.
- 2 sides of a triangle with the angle opposite to any 1 side of the triangle.
- 1 side and it's adjacent angles.
I found out, yes you could using trigonometry.
Please see this first.
https://drive.google.com/file/d/15oQ5a_OfCxIjmYx_zqjJhjbVqGNk9fxY/view?usp=drivesdk
The formula for case 1,
$ \frac{xyq}{2}$
The formula for case 2,
$ \frac{(xp)(xqr+s\sqrt{(yq)^2-(xp)^2})}{sq^2} $
The formula for case 3,
$ \frac{x^2sq}{2ps+2qr} $
But can you find the area of the triangle if 1 side and 1 angle was given to you?

No. Consider the triangle with vertices $$ (0,2) \\ (0,0) \\ (n, 0) $$ It's got one sides equal to 2, and one angle that's 90 degrees, But its area is $n$, which can be any number.