How to find the inverse Laplace transform of this function?

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$F(s) = \dfrac{s}{s+3}$ I can't find this term in any Laplace lists around

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Hint: $F(s) = \dfrac{s}{s+3} = \dfrac{(s+3)-3}{s+3} = 1-\dfrac{3}{s+3}$.

Can you find $1$ and $\dfrac{1}{s+3}$ in your Laplace table?