How to find the nth term of this sequence?

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How do I find the $n^{th}$ term, and what is it?

$$ 1, \dfrac{1}{4}, \dfrac{1}{9}, \dfrac{1}{16}, \dfrac{1}{25},\dots$$

I mean I want to find out the relation how $n^{th}$ term depends on $n$. I'm really stuck on this question.

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Unless this is a trick question, the answer is $$\frac{1}{n^2}.$$ Then the sequence continues $$\frac{1}{36}, \frac{1}{49}, \frac{1}{81}, \frac{1}{100}, \frac{1}{121}, \frac{1}{144}, \frac{1}{169}, \frac{1}{196}, \ldots$$

If you look up just 1, 4, 9, 16, 25 in the OEIS, you will get more than a hundred results. But the very first result will be A000290, The squares: $a(n) = n^2$. Often the first and simplest explanation is the best.