If $p = \frac{hv}{c}$ then how is $p^2 dp = \frac{h^3v^2}{c^3}dv$? What I arrived at is $\frac{2 h^2 v}{c^2}dv$.
2026-03-27 14:21:46.1774621306
How to find this derivative?
33 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
2
Just note that $p=\frac{hv}{c}$ implies that $dp = \frac hc dv$ and so $$ p^2 dp = \left( \frac{hv}{c}\right)^2 \frac hc dv = \frac{h^3 v^2}{c^3} dv $$