$x^2y[''] + 2y['] +2[y] = 0$
irregular singular point $x=0$
How would I go about the reduction process to find $y2(x)$ (the second linearly independent solution)? This is a textbook solution and no one online has attempted to find the second linear independent solution or even explain how to to go about the process either.
For reference, I already got $y1(x)$ which
$y1(x)=1+x+(1/2)x^2 + ...$
and the problem only requires finding the first three nonzero terms of the series expansion
Thank you