Couldn't I just argue with the definitions $\cos(z):=\frac{1}{2}(e^{iz}+e^{-iz})$?
So $\cos(z):=\frac{1}{2}(e^{iz}+e^{-iz})=\frac{1}{2}(e^{-iz}+e^{iz})=\cos(-z)$
???
Couldn't I just argue with the definitions $\cos(z):=\frac{1}{2}(e^{iz}+e^{-iz})$?
So $\cos(z):=\frac{1}{2}(e^{iz}+e^{-iz})=\frac{1}{2}(e^{-iz}+e^{iz})=\cos(-z)$
???
Since you are told that the definition of cosine is $$\frac12\left(e^{ix} + e^{-ix} \right),$$
yes, you have proven it by using commutative property. Note that there is a slight inconsitency for confusing $z$ with $x$.