How to prove ( q or not q), which is tautology when an arbitrary premise is given? (Using natural deduction)
I tried to make steps that finally goes to HS but failed.
How to prove ( q or not q), which is tautology when an arbitrary premise is given? (Using natural deduction)
I tried to make steps that finally goes to HS but failed.
Case 1: q is true, therefore q or x is true for any x, especially for x= not q Case 2: q is false, therefore not q is true, therefore x or not q is true for any x, especially for x=q Because by law of exclused middle, q has to be false or true, those cases are exhaustive.
Edit: q or not q= not(not q and not not q)= not (not q and q)= not (False)=True using excluded middle in step 2