How to prove there is no natural deduction proof for $$\forall x(P(x)\lor Q(x))\vdash\forall xP(x) \lor ∀xQ(x).$$
I don't know how to prove this, maybe by semantic?
How to prove there is no natural deduction proof for $$\forall x(P(x)\lor Q(x))\vdash\forall xP(x) \lor ∀xQ(x).$$
I don't know how to prove this, maybe by semantic?
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