I have the equation $\frac{dN}{dt}= - Nk$ where $k$ is the decay constant.
When $time = 0$,
we get $N(t) = N(0) e^{-kt}$.
How would I rearrange this to the $y = mx + c$ format? How would I find the decay constant? Thanks in advance.
I have the equation $\frac{dN}{dt}= - Nk$ where $k$ is the decay constant.
When $time = 0$,
we get $N(t) = N(0) e^{-kt}$.
How would I rearrange this to the $y = mx + c$ format? How would I find the decay constant? Thanks in advance.
You can transform the equation into a linear equation, but then you have to take logs of $N(t)$ and $N(0)$
$\ln(N(t))=\ln \left[(N(0))\cdot e^{k\cdot t}\right]$
$\ln(N(t))=\ln (N(0))+\ln\left[ e^{k\cdot t}\right]$
$\ln(N(t))=\ln (N(0))+k\cdot t$
This is equivalent to $y=c+mx$
Let´s say the origin values are
Now you calculate the logs of $N(t)$. The values of $t$ musn´t be transformed. Two value pairs are sufficient to evaluate the value of $k$.
Remark
I have $+k$ at the function, not $-k$. But it doesn´t matter. If you have a decay then the value of k is negative.