I'm working on an equation where, given the following equations:
$nL=TE$,
$\large{R=\frac{VT_f}{2}}$, and
$qf=nT_fT^{-1}$
I should get
$\large{R=\frac{VLqf}{2E}}$
I don't trust my algebra to get $R$ in these terms and was hoping someone could show me the explicit steps involved. Thank you.
Isolating for $T_{f}$ in $qf=nT_{f}T^{-1}$ gives $T_{f}=\frac{qfT}{n}$.
Now, $nl=TE$, so $T=\frac{nl}{E}$.
Therefore, $T_{f}=\frac{qf}{n}\cdot\frac{nl}{E}=\frac{qfl}{E}$.
It follows that $R=\frac{VT_{f}}{2} =\frac{Vqfl}{2E}$, as desired.