Is it the best way for the expression of this equation:
$$x = \frac{yexp\big(z(t_1 - t_2)\big)}{1+exp\big({z(t_1 - t_2)}\big)}$$
Is it the best way for the expression of this equation:
$$x = \frac{yexp\big(z(t_1 - t_2)\big)}{1+exp\big({z(t_1 - t_2)}\big)}$$
$$x = y\sigma(z(t_1-t_2))$$
where $\sigma$ is the sigmoid function.
$$ \sigma(t) = \frac{1}{1+e^{-t}} $$