I dont know how to simplify $\ln^2\left(x\right)+2 \ln x-3$
I dont know how to get $(\ln(x)+1)(\ln(x)+3)$
But I am stuck and don't really know how to do that.
I tried something like this: $2\ln x+2\ln x-3\:,\:\:2\ln\left(x\left(x-3\right)\right),\:2\ln\left(x^2-3x\right)$
Hint:
$$\ln^2(x)+2\ln{x}-3=(\ln(x)-1)(\ln(x)+3)$$