My attempt:
$$\overline{A\oplus \overline{AB}}$$
Let $\overline{AB}=C$. Now,
$$\overline{A\oplus C}$$
$$=AC+\overline{AC}$$
$$=AC+\overline{A}+\overline{C}$$
$$=A(\overline{AB})+\overline{A}+AB$$
$$=A(\overline{A}+\overline{B})+\overline{A}+AB$$
$$=(0+A\overline{B})+\overline{A}+AB$$
$$=A\overline{B}+\overline{A}+AB$$
$$=A(B+\overline{B})+\overline{A}$$
$$=A.1+\overline{A}$$
$$=A+\overline{A}$$
$$=1$$
However, this is the wrong answer. According to my book, the correct answer is $A\overline{B}$.
My book's attempt:
$$\overline{A\oplus \overline{AB}}$$
$$=\overline{A}.\overline{\overline{AB}}+A.\overline{AB}\tag{1}$$
$$=\overline{A}.AB+A(\overline{A}+\overline{B})$$
$$=0+(0+A\overline{B})$$
$$=A\overline{B}$$
My questions:
- Why did I not get the correct answer in my attempt?
- In $(1)$, shouldn't it have been $\overline{A.\overline{AB}}+A.\overline{AB}$ instead of what it is?
You made a subtle error:
$\overline{A\oplus C} \not= AC +\color{red}{\overline{AC}}$
$\overline{A\oplus C} = AC +\color{blue}{\overline{A}.\overline{C}}$
When you back substitute $C=\overline {AB}$, you should get a sum whose terms simplify to $0$ and $A\overline{B}$.