I'm trying to simplify:
$\left[(\frac{3}{4}\right)^{7}\cdot$ $\left(\frac{3}{4}\right)^{-4}]^{2}$ $\cdot4^5$
The only advance that I have done is
$\left[(\frac{3}{4}\right)^{14}\cdot$ $\left(\frac{3}{4}\right)^{-8}]$ $\cdot4^5$ and then $\left[(\frac{3}{4}\right)^{6}]$ $\cdot4^5$
the answer is$$\frac{3^6}{4}=\frac{729}{4}$$
I do not know what to do next, can someone please guide me in how to solve this exercise.
Hint:
$$(\frac{3}{4})^6 = \frac{3^6}{4^6} $$