In a multiple choice exam , I encountered the following question. The answer to the question is $$ \frac{17}{8}.$$
The question is:
$$\frac{16^{x+1}+4^{2x}}{2^{x-3}8^{x+2}} \text{ is ? }$$
In a multiple choice exam , I encountered the following question. The answer to the question is $$ \frac{17}{8}.$$
The question is:
$$\frac{16^{x+1}+4^{2x}}{2^{x-3}8^{x+2}} \text{ is ? }$$
Hint:
Write the terms in the fraction in a common base: $2$
$4 = 2^2,\; 8 = 2^3,\;16 = 2^4$.
$$\frac{(2^4)^{x+1}+(2^2)^{2x}}{2^{x-3}(2^3)^{x+2}}$$
Then use the fact that $(a^b)^c = a^{bc}$, and follow by factoring. You'll also want to remember that $a^na^m = a^{n + m}$.