I am solving this problem
$$\int {\frac{1}{\sqrt{9x^{2}-25}}dx}$$
the step I got stuck,
$$\frac13 \ln{\left(\frac{3x+\sqrt{9x^2-25}}{3}\right)} $$
and in my textbook the answer was $\frac13 (\ln{{(3x+\sqrt{9x^2-25})}}) $
2026-04-25 00:53:38.1777078418
How to simplify this ln?
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Note that $\ln 3$ is a constant, so it will be absorbed by the constant $C$ in the antiderivative.