I am unsure how to go about solving this equation to find x. Any help greatly appreciated.
2026-03-27 04:16:58.1774585018
How to solve $16^x-10\cdot4^x+16=0$
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1
Let $4^x=t$, then $16^x=(4^x)^2=t^2$
So, your equation will be $$t^2-10t+16=0$$ which is a simple quadratic equation.
Solve for $t$ first and then solve for $x$ ($\because 4^x=t $)