Im having trouble with the following problem:
solve for all theta between (0 and 2pi) and find exact values where possible for:
$$2\cos( \frac{\pi} 3(\theta-1)) +5=4$$
This is what i did:
$2\cos(\pi/3)= 1$, so
$\theta-1 = 4-5$
$\theta-1=-1$
so $\theta =0$
The answers are 3,5.
$$2\cos(\frac{\pi}{3}(\theta-1))+5=4\to \cos(\frac{\pi}{3}(\theta-1))=-\frac{1}{2}\to \frac{\pi}{3}(\theta-1)=2k\pi\pm\frac{2\pi}{3}\\ \to \theta=6k\pm2+1$$