The question:
"Imagine unwinding (straightening out) all of the DNA from a single typical cell and laying it "end-to-end"; then the sum total length will be approximately $2$ meters. Assume the human body has $10^{14}$ cells containing DNA. How many times would the sum total length of DNA in your body wrap around the equator of the earth."
The Earth's equator is $40,075$ km
Now I got this question right by dividing the assumed total length of DNA by the distance of the equator:
$$\frac{10^{14} \cdot 2 \ m}{40,075,000 \ m} = 4,990,642$$
The answer key says the answer to the question is "about $5 * 10^6$ times around the equator". But my question is, can I solve this question with an equation that converts the distance of the equator to exponential form to arrive at the same formatted answer as the answer key? Is there a mnemonic that makes it simple to do in your head? For example, if I used the equation:
$$\frac{10^{14} \cdot 2}{10^7 \cdot 4}$$
Then solved that equation to this:
$$\frac{10^7 \cdot 2}{4}$$
From here is it possible to get $$10^6 \cdot 5$$ (the answer) without using a calculator?
Yes, it is possible. For your simpler example, $\frac{2 \cdot 10^7}{4}$, rewrite $10^7 $ as $10^1 \cdot 10^6 = 10 \cdot 10^6$. Then you have $\frac{20 \cdot 10^6}{4} = 5 \cdot 10^6$.
Now back to the original question: $$\frac{2 \cdot 10^{14}}{40,075,000}$$
First, convert the denominator to standard form (scientific notation), which is $4.0075 \cdot 10^7$. Then rewrite the numerator as $20 \cdot 10^{13}$ using the same process as before.
Then you have: $$\frac{20 \cdot 10^{13}}{4.0075 \cdot 10^7}$$
where you can now estimate the denominator as $4 \cdot 10^7$ since you will not lose any precision, except if you are using more than $3$ sig figs. Then use the laws of indices to calculate this expression (which one is it)?