I'm stumble upon the following logarithm expression. What is the value of $x$ in it? $$\log_x (x^5) = 5$$
2026-05-04 21:51:56.1777931516
How to solve a logarithm?
73 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
1
HINT:
By definition, $y=\log_b(a)$ if $a=b^y$ for $b\ne 1$.
Here, we have $b=x$, $y=x$, and $a=x^5$.
What can you conclude now?