How to solve cubic polynomial algebraically?

92 Views Asked by At

I have this characteristic equation from a matrix:

$$ 0 = \lambda^3 - \frac{3a^2}{4}\lambda - \frac{1}{4}a^3$$

Where a is some constant.

I have no idea how to go about doing this by hand, I know the answer. I feel like I just missed this in my background of learning mathematics. Any guidance would be appreciated and in general how to solve problems like this.

1

There are 1 best solutions below

0
On BEST ANSWER

This can be solved using the cubic formula, $$ax^{3}+bx^{2}+cx+d=0,\ x=\frac{\sqrt[3]{\sqrt{\left(b^{3}-4.5abc+13.5a^{2}d\right)^{2}-\left(b^{2}-3ac\right)^{3}}-\left(b^{3}-4.5abc+13.5a^{2}d\right)}-\sqrt[3]{\sqrt{\left(b^{3}-4.5abc+13.5a^{2}d\right)^{2}-\left(b^{2}-3ac\right)^{3}}+\left(b^{3}-4.5abc+13.5a^{2}d\right)}-b}{3a}$$ which reduces down greatly to give $$λ=a$$