I came across the differential equation in physics
how to solve
$\frac{kx^{1-\gamma}}{v^2} + 1=\frac{dv}{dx}$
given that
$v'(l)=0,v(l)=c,v(0)=0,\gamma>1$
I tried $\frac{1}{v}=\lambda$ but it was of no avail.
I then tried to set up a taylor series with $c_0=0$ but don't know how to proceed
Is there anyway it can be solved using the stuff taught in high school
please help