How to solve the equation of $\sqrt{x}+\sqrt{y}=\sqrt{2205}$ in integers?

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How to solve the equation of $\sqrt{x}+\sqrt{y}=\sqrt{2205}$ in integers? How in general to solve the similar equations?

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Simple factorization yields $\sqrt{2205} = 21\sqrt{5} $ $$\sqrt{x}=\sqrt{2205}-\sqrt{y}$$ $$x=2205+y-2.21\sqrt{5}\sqrt{y}$$ $$42\sqrt{5y}=2205+y-x$$ $$y\text{ is in the form of } 5k^2$$ $$y=k\sqrt{5}\Rightarrow\sqrt{x}=l{5}$$

Then we have,

$\sqrt{x}=0,\sqrt{y}=21\sqrt{5}$

$\sqrt{x}=\sqrt{5},\sqrt{y}=20\sqrt{5}$ and so on...

For these type of problems, use the fact that $a+\sqrt{b}=c+\sqrt{d}$ where b,d are not perfect squares $\Rightarrow a=c \text{ and } b=d$